b^3-4b^2=21b

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Solution for b^3-4b^2=21b equation:


Simplifying
b3 + -4b2 = 21b

Reorder the terms:
-4b2 + b3 = 21b

Solving
-4b2 + b3 = 21b

Solving for variable 'b'.

Reorder the terms:
-21b + -4b2 + b3 = 21b + -21b

Combine like terms: 21b + -21b = 0
-21b + -4b2 + b3 = 0

Factor out the Greatest Common Factor (GCF), 'b'.
b(-21 + -4b + b2) = 0

Factor a trinomial.
b((-3 + -1b)(7 + -1b)) = 0

Subproblem 1

Set the factor 'b' equal to zero and attempt to solve: Simplifying b = 0 Solving b = 0 Move all terms containing b to the left, all other terms to the right. Simplifying b = 0

Subproblem 2

Set the factor '(-3 + -1b)' equal to zero and attempt to solve: Simplifying -3 + -1b = 0 Solving -3 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1b = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1b = 0 + 3 -1b = 0 + 3 Combine like terms: 0 + 3 = 3 -1b = 3 Divide each side by '-1'. b = -3 Simplifying b = -3

Subproblem 3

Set the factor '(7 + -1b)' equal to zero and attempt to solve: Simplifying 7 + -1b = 0 Solving 7 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1b = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1b = 0 + -7 -1b = 0 + -7 Combine like terms: 0 + -7 = -7 -1b = -7 Divide each side by '-1'. b = 7 Simplifying b = 7

Solution

b = {0, -3, 7}

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